As two boats approach the marina, the velocity of boat 1 relative to boat 2 is 2.1 m/s in a direction 40.0° ea

Marcel Then: Let the velocity of boat 2 have magnitude v and direction t degrees clockwise from N.With the x axis east, the y axis north, and velocities in m/s:Boat 1 has velocity (0,0.70)Boat 2 has velocity (v sin(t), v cos(t))Relative to boat 2 the velocity of boat 1 is:(- v sin(t), 0.70 - v cos(t))Equating components:- v sin(t) = 2.1 sin(40)0.70 - v cos(t) = 2.1 cos(40)Therefore:v sin(t) = -2.1sin(40) ...(1)v cos(t) = 0.70 - 2.1cos(40) ...(2)Squaring and adding (1), (2):v^2 = 2.1^2 + 0.70^2 - 4.2*0.70cos(40)v = 1.63 m/sec.From (1) & (2):sin(t) t = 236.05deg. clockwise from N.Boat 2 is travelling with velocity 1.63m/sec. in direction S 56.05deg W....Show more